Make VMODs actually fail warm-ups
The implementation is similar to the load/discard dance when a load fails. New VGC functions are introduced iff the VCL has at least one VMOD handling events. The generated code looks like this: static unsigned vgc_inistep; static unsigned vgc_warmupstep; ... static int VGC_Load(VRT_CTX) { ... } static int VGC_Discard(VRT_CTX) { ... } static int VGC_Warmup(VRT_CTX, enum vcl_event_e ev) { vgc_warmupstep = 0; /* 4 */ if (Vmod_debug_Func._event(ctx, &vmod_priv_debug, ev)) return (1); vgc_warmupstep = 4; return (0); } static int VGC_Use(VRT_CTX, enum vcl_event_e ev) { /* 4 */ if (Vmod_debug_Func._event(ctx, &vmod_priv_debug, ev)) return (1); return (0); } static int VGC_Cooldown(VRT_CTX, enum vcl_event_e ev) { int retval = 0; /* 4 */ if (vgc_warmupstep >= 4 && Vmod_debug_Func._event(ctx, &vmod_priv_debug, ev) != 0) retval = 1; return (retval); } static int VGC_Event(VRT_CTX, enum vcl_event_e ev) { if (ev == VCL_EVENT_LOAD) return(VGC_Load(ctx)); if (ev == VCL_EVENT_WARM) return(VGC_Warmup(ctx, ev)); if (ev == VCL_EVENT_USE) return(VGC_Use(ctx, ev)); if (ev == VCL_EVENT_COLD) return(VGC_Cooldown(ctx, ev)); if (ev == VCL_EVENT_DISCARD) return(VGC_Discard(ctx)); return (1); } However, if there are no VMODs handling events, no new functions shall be generated, leading to code looking like this: static unsigned vgc_inistep; static unsigned vgc_warmupstep; ... static int VGC_Load(VRT_CTX) { ... } static int VGC_Discard(VRT_CTX) { ... } static int VGC_Event(VRT_CTX, enum vcl_event_e ev) { if (ev == VCL_EVENT_LOAD) return(VGC_Load(ctx)); if (ev == VCL_EVENT_DISCARD) return(VGC_Discard(ctx)); (void)vgc_warmupstep; return (0); }
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